F(-10)=2x^2-5x+7

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Solution for F(-10)=2x^2-5x+7 equation: 



(-10)=2F^2-5F+7

We move all terms to the left:

(-10)-(2F^2-5F+7)=0

We add all the numbers together, and all the variables

-(2F^2-5F+7)-10=0

We get rid of parentheses

-2F^2+5F-7-10=0

We add all the numbers together, and all the variables

-2F^2+5F-17=0

a = -2; b = 5; c = -17;
Δ = b2-4ac
Δ = 52-4·(-2)·(-17)
Δ = -111
Delta is less than zero, so there is no solution for the equation

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